Base | Representation |
---|---|
bin | 100101000100100101010010… |
… | …111001011100100010011011 |
3 | 210101021201120012202221102222 |
4 | 211010211102321130202123 |
5 | 132332242313421024032 |
6 | 1334432431244214255 |
7 | 46225304501213654 |
oct | 4504452271344233 |
9 | 711251505687388 |
10 | 163042644314267 |
11 | 47a4aaa7225493 |
12 | 1635290b83a38b |
13 | 6cc8b17393c83 |
14 | 2c3943dca852b |
15 | 13cb1a77d3a12 |
hex | 944952e5c89b |
163042644314267 has 2 divisors, whose sum is σ = 163042644314268. Its totient is φ = 163042644314266.
The previous prime is 163042644314191. The next prime is 163042644314327. The reversal of 163042644314267 is 762413446240361.
It is a strong prime.
It is an emirp because it is prime and its reverse (762413446240361) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 163042644314267 - 230 = 163041570572443 is a prime.
It is not a weakly prime, because it can be changed into another prime (163042614314267) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 81521322157133 + 81521322157134.
It is an arithmetic number, because the mean of its divisors is an integer number (81521322157134).
Almost surely, 2163042644314267 is an apocalyptic number.
163042644314267 is a deficient number, since it is larger than the sum of its proper divisors (1).
163042644314267 is an equidigital number, since it uses as much as digits as its factorization.
163042644314267 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13934592, while the sum is 53.
The spelling of 163042644314267 in words is "one hundred sixty-three trillion, forty-two billion, six hundred forty-four million, three hundred fourteen thousand, two hundred sixty-seven".
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