Base | Representation |
---|---|
bin | 100101000100101000010111… |
… | …010111000111111111001011 |
3 | 210101022001001220222220111001 |
4 | 211010220113113013333023 |
5 | 132332321041222204442 |
6 | 1334434134311315431 |
7 | 46225452253554115 |
oct | 4504502727077713 |
9 | 711261056886431 |
10 | 163045940428747 |
11 | 47a51438856042 |
12 | 1635348b67bb77 |
13 | 6cc922121587c |
14 | 2c396739523b5 |
15 | 13cb2ebd6a2b7 |
hex | 944a175c7fcb |
163045940428747 has 2 divisors, whose sum is σ = 163045940428748. Its totient is φ = 163045940428746.
The previous prime is 163045940428741. The next prime is 163045940428817. The reversal of 163045940428747 is 747824049540361.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 163045940428747 - 27 = 163045940428619 is a prime.
It is not a weakly prime, because it can be changed into another prime (163045940428741) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 81522970214373 + 81522970214374.
It is an arithmetic number, because the mean of its divisors is an integer number (81522970214374).
It is a 2-persistent number, because it is pandigital, and so is 2⋅163045940428747 = 326091880857494, but 3⋅163045940428747 = 489137821286241 is not.
Almost surely, 2163045940428747 is an apocalyptic number.
163045940428747 is a deficient number, since it is larger than the sum of its proper divisors (1).
163045940428747 is an equidigital number, since it uses as much as digits as its factorization.
163045940428747 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 162570240, while the sum is 64.
The spelling of 163045940428747 in words is "one hundred sixty-three trillion, forty-five billion, nine hundred forty million, four hundred twenty-eight thousand, seven hundred forty-seven".
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