Base | Representation |
---|---|
bin | 1110110101011001000001… |
… | …0000010000110010111101 |
3 | 2010202021000120211200121211 |
4 | 3231112100100100302331 |
5 | 4114212210204130432 |
6 | 54404522133124421 |
7 | 3302250122021545 |
oct | 355262020206275 |
9 | 63667016750554 |
10 | 16310411005117 |
11 | 521922a889a29 |
12 | 19b5097789711 |
13 | 9140b01c9b78 |
14 | 4055dca10325 |
15 | 1d4410581d47 |
hex | ed590410cbd |
16310411005117 has 2 divisors, whose sum is σ = 16310411005118. Its totient is φ = 16310411005116.
The previous prime is 16310411005103. The next prime is 16310411005151. The reversal of 16310411005117 is 71150011401361.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 14215267658596 + 2095143346521 = 3770314^2 + 1447461^2 .
It is an emirp because it is prime and its reverse (71150011401361) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 16310411005117 - 27 = 16310411004989 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (16310411005157) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8155205502558 + 8155205502559.
It is an arithmetic number, because the mean of its divisors is an integer number (8155205502559).
Almost surely, 216310411005117 is an apocalyptic number.
It is an amenable number.
16310411005117 is a deficient number, since it is larger than the sum of its proper divisors (1).
16310411005117 is an equidigital number, since it uses as much as digits as its factorization.
16310411005117 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2520, while the sum is 31.
Adding to 16310411005117 its reverse (71150011401361), we get a palindrome (87460422406478).
The spelling of 16310411005117 in words is "sixteen trillion, three hundred ten billion, four hundred eleven million, five thousand, one hundred seventeen".
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