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163112223631397 is a prime number
BaseRepresentation
bin100101000101100110000110…
…001001011110100000100101
3210101112101011022112110220112
4211011212012021132200211
5132334412313222201042
61334524415430342405
746233316646516645
oct4505460611364045
9711471138473815
10163112223631397
1147a77561a05267
12163642a97baa05
137002555607b41
142c3c960a94525
1513ccdcaee7982
hex94598625e825

163112223631397 has 2 divisors, whose sum is σ = 163112223631398. Its totient is φ = 163112223631396.

The previous prime is 163112223631333. The next prime is 163112223631457. The reversal of 163112223631397 is 793136322211361.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 161637684569761 + 1474539061636 = 12713681^2 + 1214306^2 .

It is a cyclic number.

It is not a de Polignac number, because 163112223631397 - 26 = 163112223631333 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (163112223631997) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 81556111815698 + 81556111815699.

It is an arithmetic number, because the mean of its divisors is an integer number (81556111815699).

Almost surely, 2163112223631397 is an apocalyptic number.

It is an amenable number.

163112223631397 is a deficient number, since it is larger than the sum of its proper divisors (1).

163112223631397 is an equidigital number, since it uses as much as digits as its factorization.

163112223631397 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1469664, while the sum is 50.

The spelling of 163112223631397 in words is "one hundred sixty-three trillion, one hundred twelve billion, two hundred twenty-three million, six hundred thirty-one thousand, three hundred ninety-seven".