Base | Representation |
---|---|
bin | 100101000101110001100000… |
… | …000101110000001111011011 |
3 | 210101120112202210021122011202 |
4 | 211011301200011300033123 |
5 | 132340112403311220011 |
6 | 1334534202541144415 |
7 | 46234232302236641 |
oct | 4505614005601733 |
9 | 711515683248152 |
10 | 163124470023131 |
11 | 47a81776755671 |
12 | 16366746b5b10b |
13 | 700375781a896 |
14 | 2c3d3a32cd191 |
15 | 13cd3961d823b |
hex | 945c601703db |
163124470023131 has 2 divisors, whose sum is σ = 163124470023132. Its totient is φ = 163124470023130.
The previous prime is 163124470023023. The next prime is 163124470023191. The reversal of 163124470023131 is 131320074421361.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-163124470023131 is a prime.
It is a super-2 number, since 2×1631244700231312 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (163124470023191) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 81562235011565 + 81562235011566.
It is an arithmetic number, because the mean of its divisors is an integer number (81562235011566).
Almost surely, 2163124470023131 is an apocalyptic number.
163124470023131 is a deficient number, since it is larger than the sum of its proper divisors (1).
163124470023131 is an equidigital number, since it uses as much as digits as its factorization.
163124470023131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 72576, while the sum is 38.
The spelling of 163124470023131 in words is "one hundred sixty-three trillion, one hundred twenty-four billion, four hundred seventy million, twenty-three thousand, one hundred thirty-one".
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