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16343000000000 = 295959277
BaseRepresentation
bin1110110111010010011010…
…1101011010011000000000
32010212101010202210011022022
43231310212231122120000
54120230431000000000
654431512012301012
73304512526634462
oct355644655323000
963771122704268
1016343000000000
115231033491153
1219bb471771768
139171a4a809ab
14407010c34132
151d51bb615585
hexedd26b5a600

16343000000000 has 400 divisors, whose sum is σ = 41659273077840. Its totient is φ = 6403200000000.

The previous prime is 16342999999981. The next prime is 16343000000083. The reversal of 16343000000000 is 34361.

It is a tau number, because it is divible by the number of its divisors (400).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 58999999862 + ... + 59000000138.

Almost surely, 216343000000000 is an apocalyptic number.

16343000000000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 16343000000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (20829636538920).

16343000000000 is an abundant number, since it is smaller than the sum of its proper divisors (25316273077840).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

16343000000000 is an frugal number, since it uses more digits than its factorization.

16343000000000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 399 (or 343 counting only the distinct ones).

The product of its (nonzero) digits is 216, while the sum is 17.

Adding to 16343000000000 its reverse (34361), we get a palindrome (16343000034361).

The spelling of 16343000000000 in words is "sixteen trillion, three hundred forty-three billion", and thus it is an aban number.