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163523505325361 is a prime number
BaseRepresentation
bin100101001011100101001000…
…011100101000010100110001
3210102222200202020121021121112
4211023211020130220110301
5132413132114330402421
61335441354500403105
746305116621321006
oct4513451034502461
9712880666537545
10163523505325361
1148115a24786285
121640bb4b0a6495
13703227b32c22c
142c548192d38ad
1513d894d07545b
hex94b948728531

163523505325361 has 2 divisors, whose sum is σ = 163523505325362. Its totient is φ = 163523505325360.

The previous prime is 163523505325337. The next prime is 163523505325363.

163523505325361 is nontrivially palindromic in base 10.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 107987013222400 + 55536492102961 = 10391680^2 + 7452281^2 .

It is a palprime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-163523505325361 is a prime.

Together with 163523505325363, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (163523505325363) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 81761752662680 + 81761752662681.

It is an arithmetic number, because the mean of its divisors is an integer number (81761752662681).

Almost surely, 2163523505325361 is an apocalyptic number.

It is an amenable number.

163523505325361 is a deficient number, since it is larger than the sum of its proper divisors (1).

163523505325361 is an equidigital number, since it uses as much as digits as its factorization.

163523505325361 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 7290000, while the sum is 50.

The spelling of 163523505325361 in words is "one hundred sixty-three trillion, five hundred twenty-three billion, five hundred five million, three hundred twenty-five thousand, three hundred sixty-one".