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16354466443313 is a prime number
BaseRepresentation
bin1110110111111101001000…
…1010011011000000110001
32010220110201212220211110222
43231333102022123000301
54120422421402141223
654441045502102425
73305366632043405
oct355772212330061
963813655824428
1016354466443313
115235987a46789
121a0173187aa15
139182b15115ab
144077bba43105
151d563d0e00c8
hexedfd229b031

16354466443313 has 2 divisors, whose sum is σ = 16354466443314. Its totient is φ = 16354466443312.

The previous prime is 16354466443283. The next prime is 16354466443321. The reversal of 16354466443313 is 31334466445361.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12792761429809 + 3561705013504 = 3576697^2 + 1887248^2 .

It is a cyclic number.

It is not a de Polignac number, because 16354466443313 - 210 = 16354466442289 is a prime.

It is not a weakly prime, because it can be changed into another prime (16354466443333) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8177233221656 + 8177233221657.

It is an arithmetic number, because the mean of its divisors is an integer number (8177233221657).

Almost surely, 216354466443313 is an apocalyptic number.

It is an amenable number.

16354466443313 is a deficient number, since it is larger than the sum of its proper divisors (1).

16354466443313 is an equidigital number, since it uses as much as digits as its factorization.

16354466443313 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 22394880, while the sum is 53.

The spelling of 16354466443313 in words is "sixteen trillion, three hundred fifty-four billion, four hundred sixty-six million, four hundred forty-three thousand, three hundred thirteen".