Base | Representation |
---|---|
bin | 1110111010000010011100… |
… | …0010111011011000101011 |
3 | 2011000220002201112002212212 |
4 | 3232200213002323120223 |
5 | 4122014213032433431 |
6 | 54505324345555335 |
7 | 3311104452455333 |
oct | 356404702733053 |
9 | 64026081462785 |
10 | 16390250280491 |
11 | 524a07aa9923a |
12 | 1a086597a5b4b |
13 | 91b794c49449 |
14 | 4094142ac0c3 |
15 | 1d65348a372b |
hex | ee8270bb62b |
16390250280491 has 2 divisors, whose sum is σ = 16390250280492. Its totient is φ = 16390250280490.
The previous prime is 16390250280451. The next prime is 16390250280541. The reversal of 16390250280491 is 19408205209361.
It is an a-pointer prime, because the next prime (16390250280541) can be obtained adding 16390250280491 to its sum of digits (50).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 16390250280491 - 26 = 16390250280427 is a prime.
It is not a weakly prime, because it can be changed into another prime (16390250280421) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8195125140245 + 8195125140246.
It is an arithmetic number, because the mean of its divisors is an integer number (8195125140246).
Almost surely, 216390250280491 is an apocalyptic number.
16390250280491 is a deficient number, since it is larger than the sum of its proper divisors (1).
16390250280491 is an equidigital number, since it uses as much as digits as its factorization.
16390250280491 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 933120, while the sum is 50.
The spelling of 16390250280491 in words is "sixteen trillion, three hundred ninety billion, two hundred fifty million, two hundred eighty thousand, four hundred ninety-one".
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