Base | Representation |
---|---|
bin | 1110111010000010011100… |
… | …0100111011011000101011 |
3 | 2011000220002202111202001221 |
4 | 3232200213010323120223 |
5 | 4122014213201223104 |
6 | 54505324405122511 |
7 | 3311104460101015 |
oct | 356404704733053 |
9 | 64026082452057 |
10 | 16390250804779 |
11 | 524a080317135 |
12 | 1a086599b9437 |
13 | 91b7950a0c87 |
14 | 4094143a71b5 |
15 | 1d6534958c54 |
hex | ee82713b62b |
16390250804779 has 2 divisors, whose sum is σ = 16390250804780. Its totient is φ = 16390250804778.
The previous prime is 16390250804731. The next prime is 16390250804813. The reversal of 16390250804779 is 97740805209361.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 16390250804779 - 219 = 16390250280491 is a prime.
It is not a weakly prime, because it can be changed into another prime (16390250805779) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8195125402389 + 8195125402390.
It is an arithmetic number, because the mean of its divisors is an integer number (8195125402390).
It is a 1-persistent number, because it is pandigital, but 2⋅16390250804779 = 32780501609558 is not.
Almost surely, 216390250804779 is an apocalyptic number.
16390250804779 is a deficient number, since it is larger than the sum of its proper divisors (1).
16390250804779 is an equidigital number, since it uses as much as digits as its factorization.
16390250804779 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 22861440, while the sum is 61.
The spelling of 16390250804779 in words is "sixteen trillion, three hundred ninety billion, two hundred fifty million, eight hundred four thousand, seven hundred seventy-nine".
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