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164010317 is a prime number
BaseRepresentation
bin10011100011010…
…01100101001101
3102102121120212012
421301221211031
5313441312232
624135151005
74031031122
oct1161514515
9372546765
10164010317
1184641419
1246b15465
1327c95c33
1417ad4749
15e5ea9b2
hex9c6994d

164010317 has 2 divisors, whose sum is σ = 164010318. Its totient is φ = 164010316.

The previous prime is 164010313. The next prime is 164010359. The reversal of 164010317 is 713010461.

164010317 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 144817156 + 19193161 = 12034^2 + 4381^2 .

It is a cyclic number.

It is not a de Polignac number, because 164010317 - 22 = 164010313 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 164010292 and 164010301.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (164010313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 82005158 + 82005159.

It is an arithmetic number, because the mean of its divisors is an integer number (82005159).

Almost surely, 2164010317 is an apocalyptic number.

It is an amenable number.

164010317 is a deficient number, since it is larger than the sum of its proper divisors (1).

164010317 is an equidigital number, since it uses as much as digits as its factorization.

164010317 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 504, while the sum is 23.

The square root of 164010317 is about 12806.6512797062. The cubic root of 164010317 is about 547.3818453288.

Adding to 164010317 its reverse (713010461), we get a palindrome (877020778).

The spelling of 164010317 in words is "one hundred sixty-four million, ten thousand, three hundred seventeen".