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16401283 is a prime number
BaseRepresentation
bin111110100100…
…001110000011
31010212021022221
4332210032003
513144320113
61343311511
7256260103
oct76441603
933767287
1016401283
119292588
1255ab597
133523402
14226d203
15168e98d
hexfa4383

16401283 has 2 divisors, whose sum is σ = 16401284. Its totient is φ = 16401282.

The previous prime is 16401257. The next prime is 16401293. The reversal of 16401283 is 38210461.

16401283 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 16401283 - 25 = 16401251 is a prime.

It is not a weakly prime, because it can be changed into another prime (16401293) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8200641 + 8200642.

It is an arithmetic number, because the mean of its divisors is an integer number (8200642).

Almost surely, 216401283 is an apocalyptic number.

16401283 is a deficient number, since it is larger than the sum of its proper divisors (1).

16401283 is an equidigital number, since it uses as much as digits as its factorization.

16401283 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1152, while the sum is 25.

The square root of 16401283 is about 4049.8497502994. The cubic root of 16401283 is about 254.0734437421.

The spelling of 16401283 in words is "sixteen million, four hundred one thousand, two hundred eighty-three".