1640542331 has 2 divisors, whose sum is σ = 1640542332. Its totient is φ = 1640542330.

The previous prime is 1640542301. The next prime is 1640542333. The reversal of 1640542331 is 1332450461.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1640542331 - 2¹⁴ = 1640525947 is a prime.

It is a super-2 number, since 2×1640542331² = 5382758279605827122, which contains 22 as substring.

It is a Sophie Germain prime.

Together with 1640542333, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 1640542294 and 1640542303.

It is not a weakly prime, because it can be changed into another prime (1640542333) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 820271165 + 820271166.

It is an arithmetic number, because the mean of its divisors is an integer number (820271166).

Almost surely, 2^1640542331 is an apocalyptic number.

1640542331 is a deficient number, since it is larger than the sum of its proper divisors (1).

1640542331 is an equidigital number, since it uses as much as digits as its factorization.

1640542331 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8640, while the sum is 29.

The square root of 1640542331 is about 40503.6088639025. The cubic root of 1640542331 is about 1179.4036848648.

Adding to 1640542331 its reverse (1332450461), we get a palindrome (2972992792).

The spelling of 1640542331 in words is "one billion, six hundred forty million, five hundred forty-two thousand, three hundred thirty-one".