Base | Representation |
---|---|
bin | 1110111010111111010110… |
… | …1001100001001101110101 |
3 | 2011002110022021001022101001 |
4 | 3232233311221201031311 |
5 | 4122301204424432201 |
6 | 54521031051203301 |
7 | 3312223606646212 |
oct | 356576551411565 |
9 | 64073267038331 |
10 | 16406601405301 |
11 | 5256000857328 |
12 | 1a0b861746531 |
13 | 92019c690823 |
14 | 40a125b20b09 |
15 | 1d6b90106301 |
hex | eebf5a61375 |
16406601405301 has 2 divisors, whose sum is σ = 16406601405302. Its totient is φ = 16406601405300.
The previous prime is 16406601405241. The next prime is 16406601405323. The reversal of 16406601405301 is 10350410660461.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 16322820102801 + 83781302500 = 4040151^2 + 289450^2 .
It is a cyclic number.
It is not a de Polignac number, because 16406601405301 - 211 = 16406601403253 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (16406601405001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8203300702650 + 8203300702651.
It is an arithmetic number, because the mean of its divisors is an integer number (8203300702651).
Almost surely, 216406601405301 is an apocalyptic number.
It is an amenable number.
16406601405301 is a deficient number, since it is larger than the sum of its proper divisors (1).
16406601405301 is an equidigital number, since it uses as much as digits as its factorization.
16406601405301 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 51840, while the sum is 37.
The spelling of 16406601405301 in words is "sixteen trillion, four hundred six billion, six hundred one million, four hundred five thousand, three hundred one".
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