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16411521307 is a prime number
BaseRepresentation
bin11110100100011001…
…11111000100011011
31120100202011122220111
433102030333010123
5232102322140212
611312255505151
71120456425616
oct172214770433
946322148814
1016411521307
116a6196a955
1232202281b7
1317170cc96c
14b1989517d
15660bd2ea7
hex3d233f11b

16411521307 has 2 divisors, whose sum is σ = 16411521308. Its totient is φ = 16411521306.

The previous prime is 16411521289. The next prime is 16411521349. The reversal of 16411521307 is 70312511461.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 16411521307 - 215 = 16411488539 is a prime.

It is a super-2 number, since 2×164115213072 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (16411522307) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8205760653 + 8205760654.

It is an arithmetic number, because the mean of its divisors is an integer number (8205760654).

Almost surely, 216411521307 is an apocalyptic number.

16411521307 is a deficient number, since it is larger than the sum of its proper divisors (1).

16411521307 is an equidigital number, since it uses as much as digits as its factorization.

16411521307 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5040, while the sum is 31.

The spelling of 16411521307 in words is "sixteen billion, four hundred eleven million, five hundred twenty-one thousand, three hundred seven".