Base | Representation |
---|---|
bin | 11110100101111011… |
… | …10110110011111101 |
3 | 1120101122021112121122 |
4 | 33102331312303331 |
5 | 232114112120131 |
6 | 11313434240325 |
7 | 1121003344301 |
oct | 172275666375 |
9 | 46348245548 |
10 | 16424332541 |
11 | 6a69120151 |
12 | 32245860a5 |
13 | 1719966c86 |
14 | b1b46bd01 |
15 | 661db3d7b |
hex | 3d2f76cfd |
16424332541 has 2 divisors, whose sum is σ = 16424332542. Its totient is φ = 16424332540.
The previous prime is 16424332471. The next prime is 16424332567. The reversal of 16424332541 is 14523342461.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11528531641 + 4895800900 = 107371^2 + 69970^2 .
It is an emirp because it is prime and its reverse (14523342461) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 16424332541 - 226 = 16357223677 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (16424392541) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8212166270 + 8212166271.
It is an arithmetic number, because the mean of its divisors is an integer number (8212166271).
Almost surely, 216424332541 is an apocalyptic number.
It is an amenable number.
16424332541 is a deficient number, since it is larger than the sum of its proper divisors (1).
16424332541 is an equidigital number, since it uses as much as digits as its factorization.
16424332541 is an evil number, because the sum of its binary digits is even.
The product of its digits is 69120, while the sum is 35.
The spelling of 16424332541 in words is "sixteen billion, four hundred twenty-four million, three hundred thirty-two thousand, five hundred forty-one".
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