Base | Representation |
---|---|
bin | 100101010111000101110110… |
… | …011010111011010110011111 |
3 | 210112210022120112212112002212 |
4 | 211113011312122323112133 |
5 | 133014112144424112112 |
6 | 1341245021254311035 |
7 | 46416222512323055 |
oct | 4527056632732637 |
9 | 715708515775085 |
10 | 164314550613407 |
11 | 483a0456171387 |
12 | 1651931665847b |
13 | 708ba4602407c |
14 | 2c80c1c2721d5 |
15 | 13ee2ea134522 |
hex | 9571766bb59f |
164314550613407 has 2 divisors, whose sum is σ = 164314550613408. Its totient is φ = 164314550613406.
The previous prime is 164314550613349. The next prime is 164314550613419. The reversal of 164314550613407 is 704316055413461.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 164314550613407 - 226 = 164314483504543 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (164314550613457) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 82157275306703 + 82157275306704.
It is an arithmetic number, because the mean of its divisors is an integer number (82157275306704).
Almost surely, 2164314550613407 is an apocalyptic number.
164314550613407 is a deficient number, since it is larger than the sum of its proper divisors (1).
164314550613407 is an equidigital number, since it uses as much as digits as its factorization.
164314550613407 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3628800, while the sum is 50.
The spelling of 164314550613407 in words is "one hundred sixty-four trillion, three hundred fourteen billion, five hundred fifty million, six hundred thirteen thousand, four hundred seven".
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