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1643317489213 is a prime number
BaseRepresentation
bin10111111010011101010…
…110101110111000111101
312211002200121202221010121
4113322131112232320331
5203411003234123323
63254532444534541
7226503640121041
oct27723526567075
95732617687117
101643317489213
11583a21977254
1222659b851451
13bbc6c3a226a
1459773708021
152cb2e475a5d
hex17e9d5aee3d

1643317489213 has 2 divisors, whose sum is σ = 1643317489214. Its totient is φ = 1643317489212.

The previous prime is 1643317489147. The next prime is 1643317489217. The reversal of 1643317489213 is 3129847133461.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 878415068644 + 764902420569 = 937238^2 + 874587^2 .

It is a cyclic number.

It is not a de Polignac number, because 1643317489213 - 217 = 1643317358141 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1643317489217) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 821658744606 + 821658744607.

It is an arithmetic number, because the mean of its divisors is an integer number (821658744607).

Almost surely, 21643317489213 is an apocalyptic number.

It is an amenable number.

1643317489213 is a deficient number, since it is larger than the sum of its proper divisors (1).

1643317489213 is an equidigital number, since it uses as much as digits as its factorization.

1643317489213 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 2612736, while the sum is 52.

The spelling of 1643317489213 in words is "one trillion, six hundred forty-three billion, three hundred seventeen million, four hundred eighty-nine thousand, two hundred thirteen".