Base | Representation |
---|---|
bin | 1110111100100110000011… |
… | …0111110000011100111101 |
3 | 2011012002110120102021211111 |
4 | 3233021200313300130331 |
5 | 4123224140021303423 |
6 | 54541430432122021 |
7 | 3314221025012023 |
oct | 357114067603475 |
9 | 64162416367744 |
10 | 16434170103613 |
11 | 5266768649419 |
12 | 1a15076396311 |
13 | 92297412a672 |
14 | 40b5bd2bc713 |
15 | 1d775557460d |
hex | ef260df073d |
16434170103613 has 2 divisors, whose sum is σ = 16434170103614. Its totient is φ = 16434170103612.
The previous prime is 16434170103563. The next prime is 16434170103649. The reversal of 16434170103613 is 31630107143461.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11440920648249 + 4993249455364 = 3382443^2 + 2234558^2 .
It is a cyclic number.
It is not a de Polignac number, because 16434170103613 - 217 = 16434169972541 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (16434170103913) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8217085051806 + 8217085051807.
It is an arithmetic number, because the mean of its divisors is an integer number (8217085051807).
Almost surely, 216434170103613 is an apocalyptic number.
It is an amenable number.
16434170103613 is a deficient number, since it is larger than the sum of its proper divisors (1).
16434170103613 is an equidigital number, since it uses as much as digits as its factorization.
16434170103613 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 108864, while the sum is 40.
The spelling of 16434170103613 in words is "sixteen trillion, four hundred thirty-four billion, one hundred seventy million, one hundred three thousand, six hundred thirteen".
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