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164351060430503 is a prime number
BaseRepresentation
bin100101010111100111110110…
…100100110100111010100111
3210112220210210222112101201212
4211113213312210310322213
5133020211432432234003
61341313500154342035
746421654326542362
oct4527476644647247
9715823728471655
10164351060430503
1148404990a98341
121652440572a91b
137092313c9653b
142c828c30b90d9
1514002354ecdd8
hex9579f6934ea7

164351060430503 has 2 divisors, whose sum is σ = 164351060430504. Its totient is φ = 164351060430502.

The previous prime is 164351060430499. The next prime is 164351060430511. The reversal of 164351060430503 is 305034060153461.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 164351060430503 - 22 = 164351060430499 is a prime.

It is a super-2 number, since 2×1643510604305032 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (164351060430203) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 82175530215251 + 82175530215252.

It is an arithmetic number, because the mean of its divisors is an integer number (82175530215252).

Almost surely, 2164351060430503 is an apocalyptic number.

164351060430503 is a deficient number, since it is larger than the sum of its proper divisors (1).

164351060430503 is an equidigital number, since it uses as much as digits as its factorization.

164351060430503 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 388800, while the sum is 41.

The spelling of 164351060430503 in words is "one hundred sixty-four trillion, three hundred fifty-one billion, sixty million, four hundred thirty thousand, five hundred three".