164401301 has 2 divisors, whose sum is σ = 164401302. Its totient is φ = 164401300.

The previous prime is 164401247. The next prime is 164401331. The reversal of 164401301 is 103104461.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 104571076 + 59830225 = 10226^2 + 7735^2 .

It is a cyclic number.

It is not a de Polignac number, because 164401301 - 2¹⁰ = 164400277 is a prime.

It is a super-3 number, since 3×164401301³ (a number of 26 digits) contains 333 as substring.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (164401331) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 82200650 + 82200651.

It is an arithmetic number, because the mean of its divisors is an integer number (82200651).

Almost surely, 2^164401301 is an apocalyptic number.

It is an amenable number.

164401301 is a deficient number, since it is larger than the sum of its proper divisors (1).

164401301 is an equidigital number, since it uses as much as digits as its factorization.

164401301 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 288, while the sum is 20.

The square root of 164401301 is about 12821.9070734427. The cubic root of 164401301 is about 547.8164677899.

Adding to 164401301 its reverse (103104461), we get a palindrome (267505762).

The spelling of 164401301 in words is "one hundred sixty-four million, four hundred one thousand, three hundred one".