Base | Representation |
---|---|
bin | 11110100111110101… |
… | …11101100111111110 |
3 | 1120102202102101010102 |
4 | 33103322331213332 |
5 | 232132212214410 |
6 | 11315205441102 |
7 | 1121256452102 |
oct | 172372754776 |
9 | 46382371112 |
10 | 16440351230 |
11 | 6a77171236 |
12 | 3229a10192 |
13 | 17200851a4 |
14 | b1d63b902 |
15 | 6634ca2a5 |
hex | 3d3ebd9fe |
16440351230 has 16 divisors (see below), whose sum is σ = 29618863920. Its totient is φ = 6570311232.
The previous prime is 16440351223. The next prime is 16440351233. The reversal of 16440351230 is 3215304461.
It is a super-3 number, since 3×164403512303 (a number of 32 digits) contains 333 as substring.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 16440351193 and 16440351202.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (16440351233) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 716804 + ... + 739383.
It is an arithmetic number, because the mean of its divisors is an integer number (1851178995).
Almost surely, 216440351230 is an apocalyptic number.
16440351230 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
16440351230 is a deficient number, since it is larger than the sum of its proper divisors (13178512690).
16440351230 is a wasteful number, since it uses less digits than its factorization.
16440351230 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1457323.
The product of its (nonzero) digits is 8640, while the sum is 29.
Adding to 16440351230 its reverse (3215304461), we get a palindrome (19655655691).
The spelling of 16440351230 in words is "sixteen billion, four hundred forty million, three hundred fifty-one thousand, two hundred thirty".
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