Base | Representation |
---|---|
bin | 1001100100011101001… |
… | …0100001100011011101 |
3 | 120201100122121221122012 |
4 | 2121013102201203131 |
5 | 10143200111424423 |
6 | 203305421201005 |
7 | 14610050463632 |
oct | 2310722414335 |
9 | 521318557565 |
10 | 164404795613 |
11 | 637a6248313 |
12 | 27a42a00165 |
13 | 126709bb666 |
14 | 7d5891a189 |
15 | 4423522078 |
hex | 26474a18dd |
164404795613 has 2 divisors, whose sum is σ = 164404795614. Its totient is φ = 164404795612.
The previous prime is 164404795483. The next prime is 164404795669. The reversal of 164404795613 is 316597404461.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 142202901604 + 22201894009 = 377098^2 + 149003^2 .
It is a cyclic number.
It is not a de Polignac number, because 164404795613 - 212 = 164404791517 is a prime.
It is a super-3 number, since 3×1644047956133 (a number of 35 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (164404795213) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 82202397806 + 82202397807.
It is an arithmetic number, because the mean of its divisors is an integer number (82202397807).
Almost surely, 2164404795613 is an apocalyptic number.
It is an amenable number.
164404795613 is a deficient number, since it is larger than the sum of its proper divisors (1).
164404795613 is an equidigital number, since it uses as much as digits as its factorization.
164404795613 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2177280, while the sum is 50.
The spelling of 164404795613 in words is "one hundred sixty-four billion, four hundred four million, seven hundred ninety-five thousand, six hundred thirteen".
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