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1644064134997 is a prime number
BaseRepresentation
bin10111111011001001110…
…110111101011101010101
312211011121122201110121011
4113323021312331131111
5203414020404304442
63255134520052221
7226531304366644
oct27731166753525
95734548643534
101644064134997
11584275386289
12226769904071
13bc05ac940bb
145980494535b
152cb74cae117
hex17ec9dbd755

1644064134997 has 2 divisors, whose sum is σ = 1644064134998. Its totient is φ = 1644064134996.

The previous prime is 1644064134959. The next prime is 1644064135003. The reversal of 1644064134997 is 7994314604461.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1566404936721 + 77659198276 = 1251561^2 + 278674^2 .

It is a cyclic number.

It is not a de Polignac number, because 1644064134997 - 239 = 1094308321109 is a prime.

It is a super-3 number, since 3×16440641349973 (a number of 38 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1644064134917) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 822032067498 + 822032067499.

It is an arithmetic number, because the mean of its divisors is an integer number (822032067499).

Almost surely, 21644064134997 is an apocalyptic number.

It is an amenable number.

1644064134997 is a deficient number, since it is larger than the sum of its proper divisors (1).

1644064134997 is an equidigital number, since it uses as much as digits as its factorization.

1644064134997 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 15676416, while the sum is 58.

The spelling of 1644064134997 in words is "one trillion, six hundred forty-four billion, sixty-four million, one hundred thirty-four thousand, nine hundred ninety-seven".