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164415569933 is a prime number
BaseRepresentation
bin1001100100011111101…
…1101000000000001101
3120201101101220100020002
42121013323220000031
510143210341214213
6203310444134045
714610241166636
oct2310773500015
9521341810202
10164415569933
116380133720a
1227a46537325
1312672cc17b4
147d5a12288d
15442444e658
hex2647ee800d

164415569933 has 2 divisors, whose sum is σ = 164415569934. Its totient is φ = 164415569932.

The previous prime is 164415569849. The next prime is 164415569947. The reversal of 164415569933 is 339965514461.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 154478869444 + 9936700489 = 393038^2 + 99683^2 .

It is a cyclic number.

It is not a de Polignac number, because 164415569933 - 224 = 164398792717 is a prime.

It is a super-3 number, since 3×1644155699333 (a number of 35 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (164415569033) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 82207784966 + 82207784967.

It is an arithmetic number, because the mean of its divisors is an integer number (82207784967).

Almost surely, 2164415569933 is an apocalyptic number.

It is an amenable number.

164415569933 is a deficient number, since it is larger than the sum of its proper divisors (1).

164415569933 is an equidigital number, since it uses as much as digits as its factorization.

164415569933 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 10497600, while the sum is 56.

The spelling of 164415569933 in words is "one hundred sixty-four billion, four hundred fifteen million, five hundred sixty-nine thousand, nine hundred thirty-three".