16442664001241 has 2 divisors, whose sum is σ = 16442664001242. Its totient is φ = 16442664001240.

The previous prime is 16442664001223. The next prime is 16442664001243. The reversal of 16442664001241 is 14210046624461.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12689838798400 + 3752825202841 = 3562280^2 + 1937221^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-16442664001241 is a prime.

It is a super-3 number, since 3×16442664001241³ (a number of 41 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

Together with 16442664001243, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (16442664001243) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8221332000620 + 8221332000621.

It is an arithmetic number, because the mean of its divisors is an integer number (8221332000621).

Almost surely, 2^{16442664001241} is an apocalyptic number.

It is an amenable number.

16442664001241 is a deficient number, since it is larger than the sum of its proper divisors (1).

16442664001241 is an equidigital number, since it uses as much as digits as its factorization.

16442664001241 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 221184, while the sum is 41.

The spelling of 16442664001241 in words is "sixteen trillion, four hundred forty-two billion, six hundred sixty-four million, one thousand, two hundred forty-one".