Base | Representation |
---|---|
bin | 1110111101001000100001… |
… | …1001101001101010101011 |
3 | 2011012222100102211001110102 |
4 | 3233102020121221222223 |
5 | 4123402112322002411 |
6 | 54550000534540015 |
7 | 3314666233225463 |
oct | 357221031515253 |
9 | 64188312731412 |
10 | 16443423234731 |
11 | 526a686811819 |
12 | 1a16a1920760b |
13 | 9237ba17858c |
14 | 40bc1a186ba3 |
15 | 1d7ae7aa2d3b |
hex | ef488669aab |
16443423234731 has 2 divisors, whose sum is σ = 16443423234732. Its totient is φ = 16443423234730.
The previous prime is 16443423234691. The next prime is 16443423234757. The reversal of 16443423234731 is 13743232434461.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 16443423234731 - 210 = 16443423233707 is a prime.
It is a super-3 number, since 3×164434232347313 (a number of 41 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (16443423234781) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8221711617365 + 8221711617366.
It is an arithmetic number, because the mean of its divisors is an integer number (8221711617366).
Almost surely, 216443423234731 is an apocalyptic number.
16443423234731 is a deficient number, since it is larger than the sum of its proper divisors (1).
16443423234731 is an equidigital number, since it uses as much as digits as its factorization.
16443423234731 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 3483648, while the sum is 47.
The spelling of 16443423234731 in words is "sixteen trillion, four hundred forty-three billion, four hundred twenty-three million, two hundred thirty-four thousand, seven hundred thirty-one".
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