Base | Representation |
---|---|
bin | 1110111101100110000111… |
… | …1010001111101000011011 |
3 | 2011020201212002011120021012 |
4 | 3233121201322033220123 |
5 | 4124014400023331021 |
6 | 54553353122004135 |
7 | 3315400135436153 |
oct | 357314172175033 |
9 | 64221762146235 |
10 | 16451367402011 |
11 | 5272a93015223 |
12 | 1a184757a664b |
13 | 924484c70489 |
14 | 40c371279763 |
15 | 1d7e1022035b |
hex | ef661e8fa1b |
16451367402011 has 2 divisors, whose sum is σ = 16451367402012. Its totient is φ = 16451367402010.
The previous prime is 16451367401957. The next prime is 16451367402013. The reversal of 16451367402011 is 11020476315461.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-16451367402011 is a prime.
Together with 16451367402013, it forms a pair of twin primes.
It is a Chen prime.
It is a self number, because there is not a number n which added to its sum of digits gives 16451367402011.
It is not a weakly prime, because it can be changed into another prime (16451367402013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8225683701005 + 8225683701006.
It is an arithmetic number, because the mean of its divisors is an integer number (8225683701006).
Almost surely, 216451367402011 is an apocalyptic number.
16451367402011 is a deficient number, since it is larger than the sum of its proper divisors (1).
16451367402011 is an equidigital number, since it uses as much as digits as its factorization.
16451367402011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 120960, while the sum is 41.
The spelling of 16451367402011 in words is "sixteen trillion, four hundred fifty-one billion, three hundred sixty-seven million, four hundred two thousand, eleven".
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