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16452503342081 is a prime number
BaseRepresentation
bin1110111101101010010110…
…0111100000110000000001
32011020211210020122022002122
43233122211213200300001
54124024211323421311
654554101541054025
73315440240660612
oct357324547406001
964224706568078
1016452503342081
115273516247874
121a187320b7315
139246063c5a71
1440c43c091c09
151d7e79d050db
hexef6a59e0c01

16452503342081 has 2 divisors, whose sum is σ = 16452503342082. Its totient is φ = 16452503342080.

The previous prime is 16452503342069. The next prime is 16452503342083. The reversal of 16452503342081 is 18024330525461.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 15264492720400 + 1188010621681 = 3906980^2 + 1089959^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-16452503342081 is a prime.

It is a super-2 number, since 2×164525033420812 (a number of 27 digits) contains 22 as substring.

It is a Sophie Germain prime.

Together with 16452503342083, it forms a pair of twin primes.

It is a Chen prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (16452503342083) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8226251671040 + 8226251671041.

It is an arithmetic number, because the mean of its divisors is an integer number (8226251671041).

Almost surely, 216452503342081 is an apocalyptic number.

It is an amenable number.

16452503342081 is a deficient number, since it is larger than the sum of its proper divisors (1).

16452503342081 is an equidigital number, since it uses as much as digits as its factorization.

16452503342081 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 691200, while the sum is 44.

The spelling of 16452503342081 in words is "sixteen trillion, four hundred fifty-two billion, five hundred three million, three hundred forty-two thousand, eighty-one".