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164831231 is a prime number
BaseRepresentation
bin10011101001100…
…01111111111111
3102111011021221102
421310301333333
5314144044411
624204523315
74041020345
oct1164617777
9374137842
10164831231
1185052164
124725053b
13281c2796
1417c69995
15e70dd3b
hex9d31fff

164831231 has 2 divisors, whose sum is σ = 164831232. Its totient is φ = 164831230.

The previous prime is 164831207. The next prime is 164831237. The reversal of 164831231 is 132138461.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-164831231 is a prime.

It is a super-2 number, since 2×1648312312 = 54338669425950722, which contains 22 as substring.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 164831194 and 164831203.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (164831237) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 82415615 + 82415616.

It is an arithmetic number, because the mean of its divisors is an integer number (82415616).

Almost surely, 2164831231 is an apocalyptic number.

164831231 is a deficient number, since it is larger than the sum of its proper divisors (1).

164831231 is an equidigital number, since it uses as much as digits as its factorization.

164831231 is an evil number, because the sum of its binary digits is even.

The product of its digits is 3456, while the sum is 29.

The square root of 164831231 is about 12838.6615735442. The cubic root of 164831231 is about 548.2935883544.

Adding to 164831231 its reverse (132138461), we get a palindrome (296969692).

The spelling of 164831231 in words is "one hundred sixty-four million, eight hundred thirty-one thousand, two hundred thirty-one".