Search a number
-
+
164904281 is a prime number
BaseRepresentation
bin10011101010000…
…11110101011001
3102111022000010222
421311003311121
5314203414111
624210245425
74041443333
oct1165036531
9374260128
10164904281
11850a2033
1247286875
1328219ac9
1417c88453
15e7257db
hex9d43d59

164904281 has 2 divisors, whose sum is σ = 164904282. Its totient is φ = 164904280.

The previous prime is 164904251. The next prime is 164904323. The reversal of 164904281 is 182409461.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 161518681 + 3385600 = 12709^2 + 1840^2 .

It is a cyclic number.

It is not a de Polignac number, because 164904281 - 26 = 164904217 is a prime.

It is a super-2 number, since 2×1649042812 = 54386843784253922, which contains 22 as substring.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (164904251) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 82452140 + 82452141.

It is an arithmetic number, because the mean of its divisors is an integer number (82452141).

Almost surely, 2164904281 is an apocalyptic number.

It is an amenable number.

164904281 is a deficient number, since it is larger than the sum of its proper divisors (1).

164904281 is an equidigital number, since it uses as much as digits as its factorization.

164904281 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 13824, while the sum is 35.

The square root of 164904281 is about 12841.5061811300. The cubic root of 164904281 is about 548.3745740814.

The spelling of 164904281 in words is "one hundred sixty-four million, nine hundred four thousand, two hundred eighty-one".