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16491024413 is a prime number
BaseRepresentation
bin11110101101111000…
…10001000000011101
31120120021202211122222
433112330101000131
5232233200240123
611324215515125
71122443252243
oct172674210035
946507684588
1016491024413
116aa28317a6
123242988aa5
13172a717b16
14b2626c793
15667b896c8
hex3d6f1101d

16491024413 has 2 divisors, whose sum is σ = 16491024414. Its totient is φ = 16491024412.

The previous prime is 16491024409. The next prime is 16491024419. The reversal of 16491024413 is 31442019461.

16491024413 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 15564309049 + 926715364 = 124757^2 + 30442^2 .

It is an emirp because it is prime and its reverse (31442019461) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 16491024413 - 22 = 16491024409 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (16491024419) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8245512206 + 8245512207.

It is an arithmetic number, because the mean of its divisors is an integer number (8245512207).

Almost surely, 216491024413 is an apocalyptic number.

It is an amenable number.

16491024413 is a deficient number, since it is larger than the sum of its proper divisors (1).

16491024413 is an equidigital number, since it uses as much as digits as its factorization.

16491024413 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 20736, while the sum is 35.

The spelling of 16491024413 in words is "sixteen billion, four hundred ninety-one million, twenty-four thousand, four hundred thirteen".