Base | Representation |
---|---|
bin | 10011101010001… |
… | …01010101001101 |
3 | 102111022022120002 |
4 | 21311011111031 |
5 | 314204113123 |
6 | 24210334045 |
7 | 4041500243 |
oct | 1165052515 |
9 | 374268502 |
10 | 164910413 |
11 | 850a66a8 |
12 | 4728a325 |
13 | 2821c835 |
14 | 17c8a793 |
15 | e727528 |
hex | 9d4554d |
164910413 has 2 divisors, whose sum is σ = 164910414. Its totient is φ = 164910412.
The previous prime is 164910409. The next prime is 164910419. The reversal of 164910413 is 314019461.
164910413 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 121837444 + 43072969 = 11038^2 + 6563^2 .
It is a cyclic number.
It is not a de Polignac number, because 164910413 - 22 = 164910409 is a prime.
It is a Chen prime.
It is equal to p9234218 and since 164910413 and 9234218 have the same sum of digits, it is a Honaker prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (164910419) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 82455206 + 82455207.
It is an arithmetic number, because the mean of its divisors is an integer number (82455207).
Almost surely, 2164910413 is an apocalyptic number.
It is an amenable number.
164910413 is a deficient number, since it is larger than the sum of its proper divisors (1).
164910413 is an equidigital number, since it uses as much as digits as its factorization.
164910413 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2592, while the sum is 29.
The square root of 164910413 is about 12841.7449359501. The cubic root of 164910413 is about 548.3813711380.
Adding to 164910413 its reverse (314019461), we get a palindrome (478929874).
The spelling of 164910413 in words is "one hundred sixty-four million, nine hundred ten thousand, four hundred thirteen".
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