Base | Representation |
---|---|
bin | 1111000000101000000011… |
… | …1011010000111111111100 |
3 | 2011102201020020012000002221 |
4 | 3300022000323100333330 |
5 | 4130343004401333004 |
6 | 55033323031455124 |
7 | 3322222213041340 |
oct | 360120073207774 |
9 | 64381206160087 |
10 | 16503427371004 |
11 | 5293078564492 |
12 | 1a265845274a4 |
13 | 929360723362 |
14 | 410aad3d5620 |
15 | 1d945a871354 |
hex | f0280ed0ffc |
16503427371004 has 24 divisors (see below), whose sum is σ = 33459003441248. Its totient is φ = 6976008437760.
The previous prime is 16503427370993. The next prime is 16503427371037. The reversal of 16503427371004 is 40017372430561.
16503427371004 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a super-3 number, since 3×165034273710043 (a number of 41 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4037039877 + ... + 4037043964.
Almost surely, 216503427371004 is an apocalyptic number.
16503427371004 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
It is an amenable number.
16503427371004 is an abundant number, since it is smaller than the sum of its proper divisors (16955576070244).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
16503427371004 is a wasteful number, since it uses less digits than its factorization.
16503427371004 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8074083925 (or 8074083923 counting only the distinct ones).
The product of its (nonzero) digits is 423360, while the sum is 43.
The spelling of 16503427371004 in words is "sixteen trillion, five hundred three billion, four hundred twenty-seven million, three hundred seventy-one thousand, four".
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