Base | Representation |
---|---|
bin | 100101100011001011110110… |
… | …110110101001110011011011 |
3 | 210122201202202011222121122111 |
4 | 211203023312312221303123 |
5 | 133121221224304201324 |
6 | 1343122505032533151 |
7 | 46533243523106002 |
oct | 4543136666516333 |
9 | 718652664877574 |
10 | 165145634053339 |
11 | 486909630a3605 |
12 | 166323b68511b7 |
13 | 711c221968a44 |
14 | 2cad13c8adc39 |
15 | 1415c3c214794 |
hex | 9632f6da9cdb |
165145634053339 has 2 divisors, whose sum is σ = 165145634053340. Its totient is φ = 165145634053338.
The previous prime is 165145634053331. The next prime is 165145634053397. The reversal of 165145634053339 is 933350436541561.
It is an a-pointer prime, because the next prime (165145634053397) can be obtained adding 165145634053339 to its sum of digits (58).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 165145634053339 - 23 = 165145634053331 is a prime.
It is not a weakly prime, because it can be changed into another prime (165145634053331) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 82572817026669 + 82572817026670.
It is an arithmetic number, because the mean of its divisors is an integer number (82572817026670).
Almost surely, 2165145634053339 is an apocalyptic number.
165145634053339 is a deficient number, since it is larger than the sum of its proper divisors (1).
165145634053339 is an equidigital number, since it uses as much as digits as its factorization.
165145634053339 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 52488000, while the sum is 58.
The spelling of 165145634053339 in words is "one hundred sixty-five trillion, one hundred forty-five billion, six hundred thirty-four million, fifty-three thousand, three hundred thirty-nine".
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