Base | Representation |
---|---|
bin | 1111000011011001110010… |
… | …0110010001011110010111 |
3 | 2011121021101010220012022121 |
4 | 3300312130212101132113 |
5 | 4132133211341121411 |
6 | 55111253111040411 |
7 | 3325531405016113 |
oct | 360663446213627 |
9 | 64537333805277 |
10 | 16551136270231 |
11 | 530132aa34622 |
12 | 1a3387a070107 |
13 | 9309c4915744 |
14 | 413117732743 |
15 | 1da7ee001571 |
hex | f0d9c991797 |
16551136270231 has 2 divisors, whose sum is σ = 16551136270232. Its totient is φ = 16551136270230.
The previous prime is 16551136270183. The next prime is 16551136270261. The reversal of 16551136270231 is 13207263115561.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 16551136270231 - 213 = 16551136262039 is a prime.
It is a super-2 number, since 2×165511362702312 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (16551136270261) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8275568135115 + 8275568135116.
It is an arithmetic number, because the mean of its divisors is an integer number (8275568135116).
Almost surely, 216551136270231 is an apocalyptic number.
16551136270231 is a deficient number, since it is larger than the sum of its proper divisors (1).
16551136270231 is an equidigital number, since it uses as much as digits as its factorization.
16551136270231 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 226800, while the sum is 43.
Adding to 16551136270231 its reverse (13207263115561), we get a palindrome (29758399385792).
The spelling of 16551136270231 in words is "sixteen trillion, five hundred fifty-one billion, one hundred thirty-six million, two hundred seventy thousand, two hundred thirty-one".
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