Base | Representation |
---|---|
bin | 1111000011011010111011… |
… | …0001100101010101000111 |
3 | 2011121022011101201111122211 |
4 | 3300312232301211111013 |
5 | 4132134322423200111 |
6 | 55111343243204251 |
7 | 3325542100053136 |
oct | 360665661452507 |
9 | 64538141644584 |
10 | 16551441225031 |
11 | 5301477092689 |
12 | 1a33944216687 |
13 | 930a42b5987b |
14 | 41314603591d |
15 | 1da81ab8d521 |
hex | f0daec65547 |
16551441225031 has 2 divisors, whose sum is σ = 16551441225032. Its totient is φ = 16551441225030.
The previous prime is 16551441225017. The next prime is 16551441225041. The reversal of 16551441225031 is 13052214415561.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 16551441225031 - 215 = 16551441192263 is a prime.
It is a super-2 number, since 2×165514412250312 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (16551441225041) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8275720612515 + 8275720612516.
It is an arithmetic number, because the mean of its divisors is an integer number (8275720612516).
Almost surely, 216551441225031 is an apocalyptic number.
16551441225031 is a deficient number, since it is larger than the sum of its proper divisors (1).
16551441225031 is an equidigital number, since it uses as much as digits as its factorization.
16551441225031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144000, while the sum is 40.
The spelling of 16551441225031 in words is "sixteen trillion, five hundred fifty-one billion, four hundred forty-one million, two hundred twenty-five thousand, thirty-one".
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