Base | Representation |
---|---|
bin | 1001101000101001100… |
… | …0111010100000000011 |
3 | 120211021002220220021202 |
4 | 2122022120322200003 |
5 | 10203001304403011 |
6 | 204013234011415 |
7 | 14650000260401 |
oct | 2321230724003 |
9 | 524232826252 |
10 | 165530544131 |
11 | 64223749897 |
12 | 280b7a16b6b |
13 | 127bccb6144 |
14 | 802423c471 |
15 | 448c29223b |
hex | 268a63a803 |
165530544131 has 2 divisors, whose sum is σ = 165530544132. Its totient is φ = 165530544130.
The previous prime is 165530544077. The next prime is 165530544149. The reversal of 165530544131 is 131445035561.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-165530544131 is a prime.
It is a super-2 number, since 2×1655305441312 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (165530544031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 82765272065 + 82765272066.
It is an arithmetic number, because the mean of its divisors is an integer number (82765272066).
Almost surely, 2165530544131 is an apocalyptic number.
165530544131 is a deficient number, since it is larger than the sum of its proper divisors (1).
165530544131 is an equidigital number, since it uses as much as digits as its factorization.
165530544131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 108000, while the sum is 38.
Adding to 165530544131 its reverse (131445035561), we get a palindrome (296975579692).
The spelling of 165530544131 in words is "one hundred sixty-five billion, five hundred thirty million, five hundred forty-four thousand, one hundred thirty-one".
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