Base | Representation |
---|---|
bin | 100101101001010000101011… |
… | …100011110000001111001111 |
3 | 210201012200101012111012212121 |
4 | 211221100223203300033033 |
5 | 133200041242302302434 |
6 | 1344042352454313411 |
7 | 46605353464111105 |
oct | 4551205343601717 |
9 | 721180335435777 |
10 | 165563130119119 |
11 | 48831a248040a7 |
12 | 1669b2b1358867 |
13 | 714c6c7ca5915 |
14 | 2cc54265a1c75 |
15 | 1421a24b227b4 |
hex | 96942b8f03cf |
165563130119119 has 2 divisors, whose sum is σ = 165563130119120. Its totient is φ = 165563130119118.
The previous prime is 165563130119111. The next prime is 165563130119129. The reversal of 165563130119119 is 911911031365561.
165563130119119 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 165563130119119 - 23 = 165563130119111 is a prime.
It is a super-2 number, since 2×1655631301191192 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (165563130119111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 82781565059559 + 82781565059560.
It is an arithmetic number, because the mean of its divisors is an integer number (82781565059560).
Almost surely, 2165563130119119 is an apocalyptic number.
165563130119119 is a deficient number, since it is larger than the sum of its proper divisors (1).
165563130119119 is an equidigital number, since it uses as much as digits as its factorization.
165563130119119 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 656100, while the sum is 52.
The spelling of 165563130119119 in words is "one hundred sixty-five trillion, five hundred sixty-three billion, one hundred thirty million, one hundred nineteen thousand, one hundred nineteen".
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