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1655641362013 is a prime number
BaseRepresentation
bin11000000101111011111…
…010100100111001011101
312212021111111022112102221
4120011323322210321131
5204111223142041023
63304331404145341
7230421223243252
oct30057372447135
95767444275387
101655641362013
115891764282a1
12228a5ab38251
13c01846729a2
145a1c2351429
152d10136d85d
hex1817bea4e5d

1655641362013 has 2 divisors, whose sum is σ = 1655641362014. Its totient is φ = 1655641362012.

The previous prime is 1655641361951. The next prime is 1655641362019. The reversal of 1655641362013 is 3102631465561.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 934427688964 + 721213673049 = 966658^2 + 849243^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1655641362013 is a prime.

It is a super-2 number, since 2×16556413620132 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1655641362019) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 827820681006 + 827820681007.

It is an arithmetic number, because the mean of its divisors is an integer number (827820681007).

Almost surely, 21655641362013 is an apocalyptic number.

It is an amenable number.

1655641362013 is a deficient number, since it is larger than the sum of its proper divisors (1).

1655641362013 is an equidigital number, since it uses as much as digits as its factorization.

1655641362013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 388800, while the sum is 43.

The spelling of 1655641362013 in words is "one trillion, six hundred fifty-five billion, six hundred forty-one million, three hundred sixty-two thousand, thirteen".