16614175490953 has 2 divisors, whose sum is σ = 16614175490954. Its totient is φ = 16614175490952.

The previous prime is 16614175490951. The next prime is 16614175491007. The reversal of 16614175490953 is 35909457141661.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12170692777104 + 4443482713849 = 3488652^2 + 2107957^2 .

It is a cyclic number.

It is not a de Polignac number, because 16614175490953 - 2¹ = 16614175490951 is a prime.

Together with 16614175490951, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 16614175490891 and 16614175490900.

It is not a weakly prime, because it can be changed into another prime (16614175490951) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8307087745476 + 8307087745477.

It is an arithmetic number, because the mean of its divisors is an integer number (8307087745477).

Almost surely, 2^{16614175490953} is an apocalyptic number.

It is an amenable number.

16614175490953 is a deficient number, since it is larger than the sum of its proper divisors (1).

16614175490953 is an equidigital number, since it uses as much as digits as its factorization.

16614175490953 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 24494400, while the sum is 61.

The spelling of 16614175490953 in words is "sixteen trillion, six hundred fourteen billion, one hundred seventy-five million, four hundred ninety thousand, nine hundred fifty-three".