Base | Representation |
---|---|
bin | 1111001001110101110010… |
… | …0111101101101010111111 |
3 | 2011222211211202101012202202 |
4 | 3302131130213231222333 |
5 | 4140441211401240433 |
6 | 55234143302342115 |
7 | 3336525152463425 |
oct | 362353447555277 |
9 | 64884752335682 |
10 | 16661732055743 |
11 | 5344223414155 |
12 | 1a511a442a93b |
13 | 93b26b693b48 |
14 | 418609ac3115 |
15 | 1dd623582ee8 |
hex | f275c9edabf |
16661732055743 has 2 divisors, whose sum is σ = 16661732055744. Its totient is φ = 16661732055742.
The previous prime is 16661732055739. The next prime is 16661732055821. The reversal of 16661732055743 is 34755023716661.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 16661732055743 - 22 = 16661732055739 is a prime.
It is a super-2 number, since 2×166617320557432 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (16661732055443) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8330866027871 + 8330866027872.
It is an arithmetic number, because the mean of its divisors is an integer number (8330866027872).
Almost surely, 216661732055743 is an apocalyptic number.
16661732055743 is a deficient number, since it is larger than the sum of its proper divisors (1).
16661732055743 is an equidigital number, since it uses as much as digits as its factorization.
16661732055743 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 19051200, while the sum is 56.
The spelling of 16661732055743 in words is "sixteen trillion, six hundred sixty-one billion, seven hundred thirty-two million, fifty-five thousand, seven hundred forty-three".
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