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1670142675493 is a prime number
BaseRepresentation
bin11000010011011100010…
…000101100101000100101
312220122221010002120211101
4120103130100230220211
5204330423011103433
63315130345440101
7231443456336155
oct30233420545045
95818833076741
101670142675493
11594337aaa796
1222b8274a0031
13c1655aa6756
145ab9a242765
152d69e4c907d
hex184dc42ca25

1670142675493 has 2 divisors, whose sum is σ = 1670142675494. Its totient is φ = 1670142675492.

The previous prime is 1670142675449. The next prime is 1670142675559. The reversal of 1670142675493 is 3945762410761.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1602915519969 + 67227155524 = 1266063^2 + 259282^2 .

It is an emirp because it is prime and its reverse (3945762410761) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1670142675493 - 213 = 1670142667301 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1670146675493) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 835071337746 + 835071337747.

It is an arithmetic number, because the mean of its divisors is an integer number (835071337747).

Almost surely, 21670142675493 is an apocalyptic number.

It is an amenable number.

1670142675493 is a deficient number, since it is larger than the sum of its proper divisors (1).

1670142675493 is an equidigital number, since it uses as much as digits as its factorization.

1670142675493 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 7620480, while the sum is 55.

The spelling of 1670142675493 in words is "one trillion, six hundred seventy billion, one hundred forty-two million, six hundred seventy-five thousand, four hundred ninety-three".