Base | Representation |
---|---|
bin | 11111001010100111… |
… | …01010111110101101 |
3 | 1121012002021202110011 |
4 | 33211103222332231 |
5 | 233231400304013 |
6 | 11404145413221 |
7 | 1131431001013 |
oct | 174523527655 |
9 | 47162252404 |
10 | 16732041133 |
11 | 710688a175 |
12 | 32ab63a211 |
13 | 1768633672 |
14 | b4a28a8b3 |
15 | 67dde6c3d |
hex | 3e54eafad |
16732041133 has 2 divisors, whose sum is σ = 16732041134. Its totient is φ = 16732041132.
The previous prime is 16732041113. The next prime is 16732041169. The reversal of 16732041133 is 33114023761.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10112916969 + 6619124164 = 100563^2 + 81358^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-16732041133 is a prime.
It is a super-2 number, since 2×167320411332 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 16732041095 and 16732041104.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (16732041113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8366020566 + 8366020567.
It is an arithmetic number, because the mean of its divisors is an integer number (8366020567).
Almost surely, 216732041133 is an apocalyptic number.
It is an amenable number.
16732041133 is a deficient number, since it is larger than the sum of its proper divisors (1).
16732041133 is an equidigital number, since it uses as much as digits as its factorization.
16732041133 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9072, while the sum is 31.
Adding to 16732041133 its reverse (33114023761), we get a palindrome (49846064894).
The spelling of 16732041133 in words is "sixteen billion, seven hundred thirty-two million, forty-one thousand, one hundred thirty-three".
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