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168004017121 is a prime number
BaseRepresentation
bin1001110001110111010…
…0011101101111100001
3121001122111012100100111
42130131310131233201
510223033012021441
6205102513051321
715065203404043
oct2343564355741
9531574170314
10168004017121
1165282984746
1228688256b41
1312ac5588325
1481ba945a93
1545844cd081
hex271dd1dbe1

168004017121 has 2 divisors, whose sum is σ = 168004017122. Its totient is φ = 168004017120.

The previous prime is 168004017119. The next prime is 168004017133. The reversal of 168004017121 is 121710400861.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 154892622096 + 13111395025 = 393564^2 + 114505^2 .

It is a cyclic number.

It is not a de Polignac number, because 168004017121 - 21 = 168004017119 is a prime.

It is a super-2 number, since 2×1680040171212 (a number of 23 digits) contains 22 as substring.

Together with 168004017119, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (168004017151) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 84002008560 + 84002008561.

It is an arithmetic number, because the mean of its divisors is an integer number (84002008561).

Almost surely, 2168004017121 is an apocalyptic number.

It is an amenable number.

168004017121 is a deficient number, since it is larger than the sum of its proper divisors (1).

168004017121 is an equidigital number, since it uses as much as digits as its factorization.

168004017121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2688, while the sum is 31.

Adding to 168004017121 its reverse (121710400861), we get a palindrome (289714417982).

The spelling of 168004017121 in words is "one hundred sixty-eight billion, four million, seventeen thousand, one hundred twenty-one".