Base | Representation |
---|---|
bin | 11111010011010111… |
… | …10010111000000001 |
3 | 1121101012110112010022 |
4 | 33221223302320001 |
5 | 233404200130133 |
6 | 11415331343225 |
7 | 1133312112263 |
oct | 175153627001 |
9 | 47335415108 |
10 | 16805473793 |
11 | 7144285219 |
12 | 3310151b15 |
13 | 177a904744 |
14 | b55d23b33 |
15 | 68559e998 |
hex | 3e9af2e01 |
16805473793 has 2 divisors, whose sum is σ = 16805473794. Its totient is φ = 16805473792.
The previous prime is 16805473781. The next prime is 16805473807. The reversal of 16805473793 is 39737450861.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 16492466929 + 313006864 = 128423^2 + 17692^2 .
It is a cyclic number.
It is not a de Polignac number, because 16805473793 - 218 = 16805211649 is a prime.
It is not a weakly prime, because it can be changed into another prime (16805473193) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8402736896 + 8402736897.
It is an arithmetic number, because the mean of its divisors is an integer number (8402736897).
Almost surely, 216805473793 is an apocalyptic number.
It is an amenable number.
16805473793 is a deficient number, since it is larger than the sum of its proper divisors (1).
16805473793 is an equidigital number, since it uses as much as digits as its factorization.
16805473793 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3810240, while the sum is 53.
The spelling of 16805473793 in words is "sixteen billion, eight hundred five million, four hundred seventy-three thousand, seven hundred ninety-three".
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