Base | Representation |
---|---|
bin | 1111010010010101111110… |
… | …1111010000111110000011 |
3 | 2012111210220101221000200122 |
4 | 3310211133233100332003 |
5 | 4200334400143130133 |
6 | 55425223001410455 |
7 | 3353216165260646 |
oct | 364453757207603 |
9 | 65453811830618 |
10 | 16807813255043 |
11 | 53a0176449338 |
12 | 1a75572799a2b |
13 | 94bc7c0b1b05 |
14 | 421706c19a5d |
15 | 1e23230cb498 |
hex | f495fbd0f83 |
16807813255043 has 2 divisors, whose sum is σ = 16807813255044. Its totient is φ = 16807813255042.
The previous prime is 16807813255019. The next prime is 16807813255081. The reversal of 16807813255043 is 34055231870861.
It is a weak prime.
It is an emirp because it is prime and its reverse (34055231870861) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 16807813255043 - 28 = 16807813254787 is a prime.
It is not a weakly prime, because it can be changed into another prime (16807813255003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8403906627521 + 8403906627522.
It is an arithmetic number, because the mean of its divisors is an integer number (8403906627522).
Almost surely, 216807813255043 is an apocalyptic number.
16807813255043 is a deficient number, since it is larger than the sum of its proper divisors (1).
16807813255043 is an equidigital number, since it uses as much as digits as its factorization.
16807813255043 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4838400, while the sum is 53.
The spelling of 16807813255043 in words is "sixteen trillion, eight hundred seven billion, eight hundred thirteen million, two hundred fifty-five thousand, forty-three".
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