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1681300521443 is a prime number
BaseRepresentation
bin11000011101110101010…
…100100000000111100011
312221201201201112220000002
4120131311110200013203
5210021300413141233
63324213453050215
7232320123430244
oct30356524400743
95851651486002
101681300521443
11599043349584
12231a2018696b
13c271361926a
145b538080ccb
152db03d476e8
hex187755201e3

1681300521443 has 2 divisors, whose sum is σ = 1681300521444. Its totient is φ = 1681300521442.

The previous prime is 1681300521419. The next prime is 1681300521541. The reversal of 1681300521443 is 3441250031861.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1681300521443 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1681300521397 and 1681300521406.

It is not a weakly prime, because it can be changed into another prime (1681300520443) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 840650260721 + 840650260722.

It is an arithmetic number, because the mean of its divisors is an integer number (840650260722).

Almost surely, 21681300521443 is an apocalyptic number.

1681300521443 is a deficient number, since it is larger than the sum of its proper divisors (1).

1681300521443 is an equidigital number, since it uses as much as digits as its factorization.

1681300521443 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 69120, while the sum is 38.

The spelling of 1681300521443 in words is "one trillion, six hundred eighty-one billion, three hundred million, five hundred twenty-one thousand, four hundred forty-three".