Base | Representation |
---|---|
bin | 11000011101110101010… |
… | …100100000000111100011 |
3 | 12221201201201112220000002 |
4 | 120131311110200013203 |
5 | 210021300413141233 |
6 | 3324213453050215 |
7 | 232320123430244 |
oct | 30356524400743 |
9 | 5851651486002 |
10 | 1681300521443 |
11 | 599043349584 |
12 | 231a2018696b |
13 | c271361926a |
14 | 5b538080ccb |
15 | 2db03d476e8 |
hex | 187755201e3 |
1681300521443 has 2 divisors, whose sum is σ = 1681300521444. Its totient is φ = 1681300521442.
The previous prime is 1681300521419. The next prime is 1681300521541. The reversal of 1681300521443 is 3441250031861.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1681300521443 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1681300521397 and 1681300521406.
It is not a weakly prime, because it can be changed into another prime (1681300520443) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 840650260721 + 840650260722.
It is an arithmetic number, because the mean of its divisors is an integer number (840650260722).
Almost surely, 21681300521443 is an apocalyptic number.
1681300521443 is a deficient number, since it is larger than the sum of its proper divisors (1).
1681300521443 is an equidigital number, since it uses as much as digits as its factorization.
1681300521443 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 69120, while the sum is 38.
The spelling of 1681300521443 in words is "one trillion, six hundred eighty-one billion, three hundred million, five hundred twenty-one thousand, four hundred forty-three".
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