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16825458022117 is a prime number
BaseRepresentation
bin1111010011010111101101…
…1100101101011011100101
32012120111110002200001202021
43310311323130231123211
54201132014223201432
655441301514143141
73354412351312363
oct364657334553345
965514402601667
1016825458022117
1153a7700461a68
121a78a77a21ab1
139508318463a4
144224dc3b6633
151e2a071b5697
hexf4d7b72d6e5

16825458022117 has 2 divisors, whose sum is σ = 16825458022118. Its totient is φ = 16825458022116.

The previous prime is 16825458022103. The next prime is 16825458022129. The reversal of 16825458022117 is 71122085452861.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 16246107177316 + 579350844801 = 4030646^2 + 761151^2 .

It is a cyclic number.

It is not a de Polignac number, because 16825458022117 - 219 = 16825457497829 is a prime.

It is a super-2 number, since 2×168254580221172 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (16825458028117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8412729011058 + 8412729011059.

It is an arithmetic number, because the mean of its divisors is an integer number (8412729011059).

Almost surely, 216825458022117 is an apocalyptic number.

It is an amenable number.

16825458022117 is a deficient number, since it is larger than the sum of its proper divisors (1).

16825458022117 is an equidigital number, since it uses as much as digits as its factorization.

16825458022117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2150400, while the sum is 52.

The spelling of 16825458022117 in words is "sixteen trillion, eight hundred twenty-five billion, four hundred fifty-eight million, twenty-two thousand, one hundred seventeen".