Base | Representation |
---|---|
bin | 11000100000000110101… |
… | …000011011111011101100 |
3 | 12221222000121221011100121 |
4 | 120200012220123323230 |
5 | 210041244020143000 |
6 | 3325255422134324 |
7 | 232434415425601 |
oct | 30400650337354 |
9 | 5858017834317 |
10 | 1683738443500 |
11 | 59a0845024a3 |
12 | 2323a07213a4 |
13 | c2a117219a9 |
14 | 5b6c9b726a8 |
15 | 2dbe7daeb1a |
hex | 18806a1beec |
1683738443500 has 48 divisors (see below), whose sum is σ = 3679458662880. Its totient is φ = 673097227200.
The previous prime is 1683738443459. The next prime is 1683738443531. The reversal of 1683738443500 is 53448373861.
It is a super-2 number, since 2×16837384435002 (a number of 25 digits) contains 22 as substring.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 148030 + ... + 1841029.
It is an arithmetic number, because the mean of its divisors is an integer number (76655388810).
Almost surely, 21683738443500 is an apocalyptic number.
1683738443500 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1683738443500 is an abundant number, since it is smaller than the sum of its proper divisors (1995720219380).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1683738443500 is a wasteful number, since it uses less digits than its factorization.
1683738443500 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1990771 (or 1990759 counting only the distinct ones).
The product of its (nonzero) digits is 5806080, while the sum is 52.
The spelling of 1683738443500 in words is "one trillion, six hundred eighty-three billion, seven hundred thirty-eight million, four hundred forty-three thousand, five hundred".
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